#include <stdio.h>


int main()
{
    int i,j,k,count  = 1;
    printf("There are following small exchange plans for 1 Yuan note:\n");
    for(i = 0;i <= 100;i++)
    {
        for(j = 0;j <= 100-i;j += 2)
        {
            for(k = 0;k <= 100-i-2*j;k += 5)
            {
                if(i+j+k == 100)
                {
                    printf(count%4?"%d:1*%d+2*%d+5*%d\t":"%d:1*%d+2*%d+5*%d\n",count++,i,j/2,k/5);
                }
            }
        }
    }


    return 0;
}
//熊贤豪